Tuesday, 24 January 2012

Multistep Problems in Grade VI

Hello friends Previously we have discussed about rational expressions applications word problems and today we are going to discuss a new topic called multi step problems which  you will be facing in algebra 1 in Grade VI of karnataka education board. It can be a difficult task for you to solve multi step problems in mathematics. As you have already studied about one step problem in grade V. Now we are here to tell you about multistep problems. Firstly we are going to discuss about multi step linear equations.
You are familiar with one step linear equation. Now for multi step you need to focus more as it is not that easy as one step equation problems. It can be well understood with the help of an example.
Example-Raman has a math book which consist of 300 pages. If he reads 45 pages on Monday, 65 pages on Wednesday, and 25 pages on Thursday. How many pages are left to be read?
Solution:
                 300 tells the total number of pages
                 45 tells the page read on Monday
                 65 tells the page read on Wednesday
                25 tells the page read on Thursday
And the question asked is how many pages are left?
Most of you will recognize that you need to add 45+65+25 = 135. Now you need to go to multistep.
Number of pages read by Raman is 135. But you need to find number of pages left. So for that you need to subtract 135 from 300. So when you do 300-135, you will get your answer  that is 165. So number of pages left to be read is 165.
Now we will do another example which will surely clear all your doubts about multi step problems.
Example –Rohan has bought 12  dozen of bananas  at 20 rupees per dozen. Now he sold 50 bananas at 2 rupees each and rest  bananas at 3 rupees each. Now you have tell how much profit he made.
Solution:12 dozen tells us that Rohan has 144 bananas as 12*12=144
                  He bought a dozen at the rate of 20 so total cost=20*12=240
                Now he sold 50 bananas for 2 rupees so selling price=50*2=100
                 Now the number of bananas left with him are =144-50=94
               So he sold 94 bananas for 3 rupees each so selling price =94*3=282
So total sold cost=282+100=382
Now he bought it at the cost of 240 and sold it at the cost of 382
Now profit=selling price - cost price
So profit=382-240=138
So Rohan made a profit of 138 rupees
Now we will discuss one multistep linear equation problem
Example: solve 2X+6=16
Now for solving this type problem you must know sign exchange rule as we want any number to go from left side to right side we need to change its sign. If it is ‘+’than it will converted to’- ’ and if it is multiply than it  changes to divide. Now let  see the above problem.
We need to send left side 6 to right side so the equation will be
2X=16-6
Or
2X=10
Now we need to send 2 to right side
X=10/2
Or
X=5
So this is a brief description about multistep problem and I hope that you have understood it and if anyone want to know about Properties of 2-d and 3-d figures then they can refer to internet and text books for understanding it more precisely.Read more maths topics of different grades such as Representing probability in the next session here.

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