Friday, 3 February 2012

Evaluating formulas

Hello children, in this section we are going to learn some of the concepts of algebra 2 help. We will discuss how to evaluate formulas for algebra. Chiefly variables are used for evaluating formulas.
The term variable means something that can vary or change. In other words, we can say that value of variable is not fix i.e. it keeps changing. Now we discuss the steps to evaluate formulas for algebra:
Step 1: For evaluating formulas first of all we measure what kind of variables are used in that geometric figure like rectangular is combination of length and width, then we assume variable for length and width like l = length and w = width.
Step 2: After measurement of variables, we evaluate what kind of operation is to be performed between variables like in area of rectangle, multiplication operation perform between length and width. So, area of rectangle = l * w .
Now we take some example to understand process of evaluating formulas –
Perimeter of square:
Step 1: We all know that all side of square are equal than there is only one variable exist length and we assume that l = length.
Step 2 : Now, we all know that perimeter of polygon is equal to sum of all side’s length . So perimeter of square is = l + l + l + l = 4 l.
So, formula to evaluate perimeter of square is 4l.
Area of triangle:
Step 1: We all know that there are two variable lengths and height exist in triangle. So, we assume that length = l and height = h.
Step 2 : Now we all know that area of triangle is half of multiplication of length and height . So, area of triangle = 1 * l * h.
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Perimeter of rectangle:
Step 1: We all know that there are two variable lengths and width exist in rectangle. So, we assume that l = length and w =width.
Step 2: Now, we all know that perimeter of polygon is equal to sum of all side’s length. So perimeter of rectangle is = l + b + l + b = 2 l + 2b
So, formula to evaluate perimeter of rectangle is 2l + 2b.
Area of circle :
Step 1: We all know that circle has only one variable which is radius. So we assume R = radius .
Step 2: Now we all know that area of circle is equal to mulplication of pi and square of r. So, area of circle = Π * r2.
Similarly we can evaluate formula for each and every figure of geometry like perimeter of hexagon = 6 * l, area of cube = 6 * l * l etc.

In upcoming posts we will discuss about Algebraic Expressions. Visit our website for information on ICSE class 12 syllabus

  

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