In the previous post we have discussed about Completing the Square and In today's session we are going to discuss about Variable and Expression. When we study about the algebra and finding the solution of the algebraic equations, we say that the child must have the knowledge of the variable and expression before we start the study of the equations. By the term variable, we mean the values which are unknown and the different values can be placed to these variables. Now we will say that the expression can be formed by joining the terms with the operators + and -.
So we say that x , y , z are the variables. On the other hand we have 3x, 5y, 6z as the terms which are used as the units for the formation of the algebraic expressions. So we say that 3x + 5y – 2z is the expression. We can perform the mathematical operations on the expressions.
In order to add the expressions, we need to remember that the like terms of the expressions can be added together. So if we have the two expressions 3x + 6y and 4x – 2y so to add the given expressions we will proceed as follows:
(3x + 6y) + (4x – 2y),
= ( 3x + 4x ) + ( 6y – 2y),
= 7x + 4y.
Thus we say that the coefficient of the like terms are added up. In the same way the operation of subtraction can also be performed. So if we take the two expression: 3x + 6y and 4x – 2y . If we need to find the difference of the two expressions we will write it as follows: (3x + 6y) – ( 4x – 2y).
= ( 3x – 4x ) + ( 6y + 2y),
= -x + 8y.
We can also perform the operation of multiplication and division on the algebraic expressions. Different rules are followed for solving such expressions.
If we have any idea about Pythagorean Theorem than we can solve Pythagorean Theorem Word Problems. iit Question Paper 2013 help students for upcoming 2013 iit exam.
So we say that x , y , z are the variables. On the other hand we have 3x, 5y, 6z as the terms which are used as the units for the formation of the algebraic expressions. So we say that 3x + 5y – 2z is the expression. We can perform the mathematical operations on the expressions.
In order to add the expressions, we need to remember that the like terms of the expressions can be added together. So if we have the two expressions 3x + 6y and 4x – 2y so to add the given expressions we will proceed as follows:
(3x + 6y) + (4x – 2y),
= ( 3x + 4x ) + ( 6y – 2y),
= 7x + 4y.
Thus we say that the coefficient of the like terms are added up. In the same way the operation of subtraction can also be performed. So if we take the two expression: 3x + 6y and 4x – 2y . If we need to find the difference of the two expressions we will write it as follows: (3x + 6y) – ( 4x – 2y).
= ( 3x – 4x ) + ( 6y + 2y),
= -x + 8y.
We can also perform the operation of multiplication and division on the algebraic expressions. Different rules are followed for solving such expressions.
If we have any idea about Pythagorean Theorem than we can solve Pythagorean Theorem Word Problems. iit Question Paper 2013 help students for upcoming 2013 iit exam.
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