Hello students, in this section we are going to discuss the estimating probability, Probability means predictions. Estimating probability means finding the probability. In this we are using favorable event, it means the cases which ensure the occurrence of an event.
Mathematically we have,
Probability of an event ‘A’ that is P (A) = m / n.
Where m = possible outcomes favorable to the occurrence of ‘A’.
n = total number of possible outcomes.
And n - m = possible outcomes unfavorable to the occurrence of ‘A’.
We also notice that
P (A) + P (A)' = m / n + n – m / n = 1,
That is P (A) + P (not A) = 1.
Probability sum of events in an experiment is equal to one, means if there is an experiment in which three events are occurring, as x , y , z then the probability p (x) , p (y) and p (z) are denoted as p (x) + p (y) +p (z) = 1.
Let us take an example to estimate the probability.
-Estimate the probability of getting the number less than 6 in throwing a die once.
Solution: - Total number of events are: 1, 2, 3, 4, 5, 6.
n (s) = 6,
Favorable events = a number than less than 6 = A = 1, 2, 3, 4, 5,
n (A) = 5,
Hence P (A) = n (A) / n (s) = 5 / 6.
Like this we can solve any examples for probability of Estimating.
I hope this information will be valuable for the Grade VI students.
In the next session we are going to discuss Representing probability.
Mathematically we have,
Probability of an event ‘A’ that is P (A) = m / n.
Where m = possible outcomes favorable to the occurrence of ‘A’.
n = total number of possible outcomes.
And n - m = possible outcomes unfavorable to the occurrence of ‘A’.
We also notice that
P (A) + P (A)' = m / n + n – m / n = 1,
That is P (A) + P (not A) = 1.
Probability sum of events in an experiment is equal to one, means if there is an experiment in which three events are occurring, as x , y , z then the probability p (x) , p (y) and p (z) are denoted as p (x) + p (y) +p (z) = 1.
Let us take an example to estimate the probability.
-Estimate the probability of getting the number less than 6 in throwing a die once.
Solution: - Total number of events are: 1, 2, 3, 4, 5, 6.
n (s) = 6,
Favorable events = a number than less than 6 = A = 1, 2, 3, 4, 5,
n (A) = 5,
Hence P (A) = n (A) / n (s) = 5 / 6.
Like this we can solve any examples for probability of Estimating.
I hope this information will be valuable for the Grade VI students.
In the next session we are going to discuss Representing probability.
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